Answer:
at x = 14.3 cm net magnetic field would be ZERO
Explanation:
At the position where net magnetic field would be zero
we will say that
[tex]B_1 = B_2[/tex]
here we know that
[tex]B_1 = \frac{\mu_0 i_1}{2\pi r}[/tex]
and due to another wire we have
[tex]B_2 = \frac{\mu_0 i_2}{2\pi (20 - r)}[/tex]
so here we have
[tex]B_1 = B_2[/tex]
[tex]\frac{\mu_0 i_1}{2\pi r} = \frac{\mu_0 i_2}{2\pi (20 - r)}[/tex]
[tex]\frac{20}{r} = \frac{8}{20 - r}[/tex]
[tex]5(20 - r) = 2r[/tex]
[tex]7 r = 100[/tex]
[tex]r = 14.3 cm[/tex]
