Explanation:
It is given that,
Wavelength 1, [tex]\lambda_1=410\ nm=410\times 10^{-9}\ m[/tex]
Wavelength 2, [tex]\lambda_2=750\ nm=750\times 10^{-9}\ m[/tex]
Energy of a photon having wavelength 1 is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
[tex]E_1=\dfrac{6.62\times 10^{-34}\times 3\times 10^8}{410\times 10^{-9}}[/tex]
[tex]E_1=4.84\times 10^{-19}\ J[/tex]
Energy of a photon having wavelength 2 is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
[tex]E_2=\dfrac{6.62\times 10^{-34}\times 3\times 10^8}{750\times 10^{-9}}[/tex]
[tex]E_2=2.64\times 10^{-19}\ J[/tex]
Hence, this is the required solution.
