Answer:
The absorbed energy by the person is [tex]6.74\times10^{-4}\ grays[/tex]
Explanation:
Given that,
Mass of person = 79 kg
Time = 6.0 s
Beta radiation = 3.0 C
Energy[tex]E = 1,6\times10^{-13}\ J[/tex]
We need to calculate the number of disintegration in 3 ci
[tex]N=3.0\times\dfrac{3.7\times10^{10}\ disintegration/s}{ci}\times3.0\ s[/tex]
[tex]N=3.33\times10^{11}\ disintegration[/tex]
We need to calculate the total energy of beta particle
[tex]E=3.33\times10^{11}\times1.6\times10^{-13}\ J[/tex]
[tex]E=0.05328\ J[/tex]
We need to calculate the energy absorbed by the 79 kg of person
[tex]E'=\dfrac{E}{m}[/tex]
Put the value into the formula
[tex]E'=\dfrac{0.05328}{79}[/tex]
[tex]E'=6.74\times10^{-4}\ J/kg = grays[/tex]
Hence, The absorbed energy by the person is [tex]6.74\times10^{-4}\ grays[/tex]
