Answer:
no. of electrons, n = [tex]2.25\times 10^{18}[/tex] passes through his body
Explanation:
We know the the rate of flow of charge is current and also amount of charge is an integral multiple of charge of an electron.
The two relations for current and charge are given as:
[tex]I = \frac{q}{t}[/tex]
where
q = charge
I = current
t = time = 1 min = 60 s
So, [tex]q = I\times t[/tex] (1)
Also,
q = ne (2)
n = 0, 1, 2,.....
e = charge of an electron = [tex]1.6\times 10^{-19}[/tex] C
Using eqn (1) and (2):
[tex]n = \frac{I\times t}{e}[/tex]
[tex]n = \frac{6\times 10^{-3}\times 60}{1.6\times 10^{-19}}[/tex]
n = [tex]2.25\times 10^{18}[/tex]
