Answer:
Magnetic field, B = 0.073 T
Explanation:
It is given that,
A magnetron in a microwave oven emits electromagnetic waves with a frequency 2450 MHz, [tex]f=2450\times 10^6Hz[/tex]
We need to find the magnetic field required for electrons to move in circular paths with this frequency.
The formula is given by :
[tex]B=\dfrac{m\omega}{q}[/tex]
q and m are charge and mass of electron
[tex]B=\dfrac{9.1\times 10^{-31}\times 2\pi (2450\times 10^6)}{1.6\times 10^{-19}}[/tex]
B = 0.073 T
Hence, this is the required solution.
The magnetic field strength is required for electrons to move in circular paths with this frequency is 0.0734T.
The magnetic serves as the part of the magnetic field which is not intrinsic to the material itself.
Given;
[tex]Frequency= 2450 MHz= 2450*20^6 Hz[/tex]
[tex]q= 1.6*10^-19[/tex]
To calculate magnetic field value in circular path, we use[tex]B= mw/q[/tex]
Where m= mass
q= charge
But let[tex](mw)= h[/tex] ............ eqn(1)
Then B= h/q ........ eqn(2)
Then substitute the values, we have, [tex]h= (9.1*10^-31)*2π*(2450*20^6)= 1.4*10^-20[/tex]
Then from eqn(2)
[tex]B= \frac{1.4*10^-20}{1.6*10^-19}[/tex]
[tex]B= 0.0734T[/tex]
Therefore, magnetic field strength is required for electrons to move in circular paths with this frequency is 0.0734T.
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