[tex]\bf \begin{cases} f(x) = 5x-10\\ g(x) = x + 3 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ g(-1)=(-1)+3\implies \boxed{g(-1) = 2} \\\\\\ f(~~g(-1)~~)\implies f\left( \boxed{2} \right) = 5(2)-10\implies \stackrel{f(~g(-1)~)}{f(2)}=0[/tex]
Answer:
0
Step-by-step explanation:
Evaluate g(- 1) then use this result to evaluate f(x)
g(- 1) = - 1 + 3 = 2, then
f(2) = (5 × 2) - 10 = 10 - 10 = 0
