Answer:
[tex]0.19\mu F[/tex]
Explanation:
Length of the sheet = 7.5 cm =0.075m
Width of the sheet =5.6 m
So area of the sheet A= 5.6×0.075=0.42[tex]m^2[/tex]
Value of [tex]\varepsilon _0=8.85\times 10^{-12}[/tex]
Distance d =[tex]4.1\times 10^{-2}mm=4.1\times 10^{-5}m[/tex]
Dielectric constant K = 2.1 given in question
Capacitance is given by [tex]C=\frac{K\epsilon _0A}{d}=\frac{2.1\times 8.85\times 10^{-12}\times 0.42}{4.1\times 10^{-5}}=0.19\mu F[/tex]
