Answer:
rms value of the electric field of the transmitted beam is 61.52 N/c
Explanation:
Given data
intensity I o = 13.4 W/m²
angle θ = 30°
to find out
rms value of the electric field
solution
we find here Erms
so we know that equation malus law that express as intensity of the light transmitted from the polarizer
so
Inetnsity of the transmitted light I = I o × cos ²θ
Inetnsity of the transmitted light I = 13.4 × cos ²30
Inetnsity of the transmitted light I = 10.05
so we know that
c× ε× Erms² = Inetnsity of the transmitted light
Erms² = 10.05 / 3 × [tex]10^{8}[/tex] × 8.85 × [tex]10^{-12}[/tex]
Erms = 61.52 N/c
rms value of the electric field of the transmitted beam is 61.52 N/c
