Answer:
The speed of the bullet before striking the block is 185 m/s.
Explanation:
Given that,
Mass of bullet = 16.0 g
Mass of wood block = 2450 g
Velocity of block = 1.2 m/s
We need to calculate the speed of the bullet before striking the block
Using equation of conservation of momentum
[tex]P_{i}=P_{f}[/tex]
[tex]m_{b}v_{b}=(m_{b}+m_{w})v[/tex]
[tex]16.0v=(0.016+2.450)\times1.2[/tex]
[tex]v=\dfrac{0.016+2.450}{0.0160}\times1.2[/tex]
[tex]v=185\ m/s[/tex]
Hence, The speed of the bullet before striking the block is 185 m/s.
