Answer:
The Froude number of the flow in the channel is 0.253
Explanation:
We know that Froude number for a rectangular channel is given by
[tex]F_{r}=\frac{v}{\sqrt{gy}}[/tex]
where,
v = is the velocity of flow
g = is the acceleration due to gravity
y = depth of flow
We know that velocity is calculated from the flow rate as
[tex]v=\frac{Q}{Area}\\\\\therefore v=\frac{0.95}{1.2\times 1}=0.792m/s[/tex]
Applying the given values in the equation we obtain Froude number as follows[tex]Hence\\\\F_{r}=\frac{0.792}{\sqrt{9.81\times 1}}=0.253[/tex]
