Answer:
1.89 m
Explanation:
h = 2 m
u = 3 m/s
θ = 45
Let t be the time taken
use second equation of motion in vertical direction
h = u t + 1/2 a t^2
- 2 = 3 Sin 45 t - 1/2 x 9.8 x t^2
- 2 = 2.12 t - 4.9 t^2
4.9 t^2 - 2.12 t - 2 = 0
By solving we get
t = 0.89 sec
Let x be the horizontal distance travelled
x = u Cos 45 x t
x = 3 Cos 45 x 0.89 = 1.89 m
