Answer:
35 m/s
Explanation:
m = 1840 kg
2R = 225 m
R = 112.5 m
μ = 0.9
θ = 6 degree
use the formula for the banking of road
[tex]v = \sqrt{\frac{Rg(Sin\theta +\mu Cos\theta )}{Cos\theta -\mu Sin\theta }}[/tex]
[tex]v = \sqrt{\frac{112.5\times 9.8(Sin6 +0.9 Cos6 )}{Cos6 -0.9Sin6 }}[/tex]
v = 35 m/s
