Answer:
Q=0.00274 Lt/s
Explanation:
Given that
Darcy friction factor f=0.04
Diameter of pipe d=10 mm
We know that for laminar flow
[tex]Re=\dfrac{16}{f}[/tex]
Where Re is the Reynolds number and f is the friction factor.
Now by putting the values
[tex]Re=\dfrac{16}{0.04}[/tex]
Re=400
We know that [tex]Re=\dfrac{\rho Vd}{\mu }[/tex]
[tex]\mu =8.9\times 10^{-4} Pa-sec[/tex] for water
[tex]400=\dfrac{1000 \times 0.01V}{8.9\times 10^{-4}}[/tex]
V=0.035 m/s
So volume flow rate Q=AV
[tex]Q=\dfrac{\pi}{4}\times 0.01^2\times 0.035[/tex]
Q=0.00274 Lt/s
