Respuesta :
Answer:
[tex]\mu = 1.645 [/tex]
Explanation:
By Snell's law we know at the left surface
[tex]\theta_i = 19^o[/tex]
[tex]\theta_r = ?[/tex]
[tex]\mu_1 = 1[/tex]
[tex]\mu_2 = \mu[/tex]
now we have
[tex]1 sin19 = \mu sin\theta_r[/tex]
[tex]0.33 = \mu sin\theta_r[/tex]
now on the other surface we know that
angle of incidence = [tex]\theta_r'[/tex]
[tex]\theta_e = 90 [/tex]
so again we have
[tex]\mu sin\theta_r' = 1 sin90[/tex]
so we have
[tex]\theta_r = sin^{-1}\frac{0.33}{\mu}[/tex]
[tex]\theta_r' = sin^{-1}\frac{1}{\mu}[/tex]
also we know that
[tex]\theta_r + \theta_r' = 49[/tex]
[tex]sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49[/tex]
By solving above equation we have
[tex]\mu = 1.645 [/tex]
