Respuesta :
Here is code in java to perform selection sort.
// import library
import java.util.*;
import java.lang.*;
import java.io.*;
class Solution
{
public static void main (String[] args) throws java.lang.Exception
{
try{
// creating object of Solution class
Solution obj=new Solution();
// creating object of Scanner class to read input
Scanner sc=new Scanner(System.in);
// create array of size 10
int arr[]=new int[10];
System.out.println("Please Enter 10 numbers :");
// reading input from user
for(int i=0;i<10;i++)
{
arr[i]=sc.nextInt();
}
// calling sort_fun with object "obj" to sort array
obj.sort_fun(arr);
// printing the array after selection sort
System.out.println("Array after performing selection sort:");
for (int i=0; i<10; ++i)
System.out.print(arr[i]+" ");
System.out.println();
}catch(Exception ex){
return;}
}
// creating function to perform selection sort
public static void sort_fun(int arr[])
{
for (int i = 0; i < 10-1; i++)
{
int m_idx = i;
for (int j = i+1; j < 10; j++)
if (arr[j] < arr[m_idx])
m_idx = j;
// find the minimum element and put them in the beginning
int temp = arr[m_idx];
arr[m_idx] = arr[i];
arr[i] = temp;
}
}
}
Explanation:
First create an object of "Solution" class. Then create an object of "Scanner" class to read input from user.After this create an array of size 10 of type integer and read 10 value from user in the array.In the sort_fun(),it will find the smallest element of unsorted array and put it in the beginning of the array. Then it find the second smallest number and put it after the first element. Similarly it will find the next element and put it after second element.When the loop end, the array will be sorted.
Output:
Please Enter 10 numbers :
45 34 12 90 84 1 4 56 12 6
Array after performing selection sort:
1 4 6 12 12 34 45 56 84 90
