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A force of 8800 N is exerted on a piston that has an area of 0.010 m^2. What is the force exerted by a second piston that has an area of 0.040 m^2?

Respuesta :

Explanation:

It is given that,

Force on piston, F₁ = 8800 N

Area, [tex]A_1=0.01\ m^2[/tex]

Area, [tex]A_2=0.04\ m^2[/tex]

Let F₂ is the force exerted on the second piston. Using Pascal's law as :

Pressure at piston 1 = Pressure at piston 2

[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}[/tex]

[tex]F_2=\dfrac{F_1}{A_1}\times A_2[/tex]

[tex]F_2=\dfrac{8800}{0.01}\times 0.04[/tex]

[tex]F_2=35200\ N[/tex]

So, the force exerted by a second piston is 35200 N. Hence, this is the required solution.

Answer:

the force exerted by a second piston is 35200 N

Explanation:

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