Answer:
1.479 A
Explanation:
Expression for de Broglie wave length
λ = [tex]\frac{h}{\left ( 2mKE \right )^{.5}}[/tex]
Where m is mass of neutron ,h is plank constant and KE is kinetic energy of
proton.
Kinetic Energy ( KE) = 3 / 2 kT
=1.5 X 1.38 X 10⁻²³ X 290 = 600.3 X 10⁻²³ J
[tex]\sqrt{2mKE}[/tex] = [tex]\sqrt{2\times1.67\times10^{-27}\times600.3\times10^{-23}}[/tex]
44.777 x 10⁻²⁵
λ = [tex]\frac{6.626\times10^{-34}}{44.777\times10^{-25}}[/tex]
=1.479 A.
