Explanation:
The given data is as follows.
[tex]T_{air} = 80 ^{o}C[/tex], [tex]T_{surface} = 30 ^{o}C[/tex]
Area of the flat plate is 2 × 4 = 8 [tex]m^{2}[/tex].
Average convection heat transfer coefficient [tex](h_(avg))[/tex] = [tex]\frac{(20 + 100) W/m^{2} ^{o}C}{2}[/tex] = [tex]60 W/m^{2} ^{o}C}[/tex].
Hence, formula to calculate heat transfer through convection from air to the water is given as follows.
q = [tex]h_{avg} \times A_{surface} \times (T_{air} - T_{surface})[/tex]
= [tex]60 W/m^{2} ^{o}C} \times 8 m^{2} \times [(80 - 30)]^{o}C[/tex]
= 24000 W
or, = 24 kW
Hence, the direction of heat flow is from air to the surface.
Thus, we can conclude that transfer of heat is 24 kW.
