Answer:
1
Explanation:
The escape speed of the earth is given by [tex]\sqrt{\frac{2GM}{R}}[/tex] here G is gravitational constant and M is the mass and R is the radius of the earth
Now in the question it is said that if mass is increases twice and radius is also becomes twice so escape speed [tex]\sqrt{\frac{2G2M}{2R}}=\sqrt{\frac{2GM}{R}}[/tex] it is the same before the changing the mass and radius of the earth so the escape speed will be same that is 1 times of the earth
