Answer:
Ke=electron kinetic energy=[tex]10.24*10^{33} J[/tex]
Explanation:
The electron has a mass of [tex]9.1*10^{-31} kg[/tex]
The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to [tex]3*10^{8} \frac{m}{s}[/tex]
Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:
[tex]K=\frac{1}{2} *m*v^{2}[/tex] Equation(1)
K=kinetic energy (J)
m =mass of the body (kg)
v= speed of the body[tex](\frac{m}{s} )[/tex]
for this problem We replace in the equation (1)
[tex]me=9.1*10^{-31} kg[/tex] = electron mass
[tex]ve=1.5*10^{8} \frac{m}{s}[/tex]=Half the speed of light
=electron speed
We replace in the equation (1) :
[tex]Ke=\frac{1}{2}*me*ve^{2}[/tex]
[tex]Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}[/tex]
[tex]Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}[/tex]
[tex]Ke=10.24*10^{33} J[/tex]
The energy kinetic of the electron is [tex]10.24*10^{33} Joules[/tex]
