Answer:
∝= 51.08 nm
Explanation:
It is necessary that the photon have the enough energy to get out of the ground state and the energy required to jump out of the ground state = 13.6 eV
so we have the total energy needed:
E= 13.6+10.7
E= 24.3 eV
Planck constant = 6.62*10^-34
with the E formula we could clear the wavelength variable like this....
E= hf
E= h(c/∝)
∝= h*(c/E)
∝=(6.62*10^-34) * [ 3*10^8 / 24.3*(1.6*10^-19)J ]
∝= 5.108*10^-8m
now we just need to convert to a nm distance
∝= 51.08 nm
