Respuesta :
Answer: [tex]1.94\times 10^{-34}m[/tex]
Explanation:
Formula used : [tex]\lambda=\frac{h}{m\times v}[/tex]
where,
[tex]\lambda[/tex] = wavelength =?
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
m = mass = 200 g = 0.2kg
v = velocity =[tex]17m/s[/tex]
Now put all the given values in this formula, we get
[tex]\lambda=\frac{6.626\times 10^{-34}Js}{0.2kg\times 17m/s}=1.94\times 10^{-34}m[/tex]
The de Broglie wavelength for the ball is [tex]1.94\times 10^{-34}m[/tex]
Answer:
The deBoglie wavelength is 1.95 ×10⁻³⁴ m
Explanation:
To calculate the deBoglie wavelength, we use the formula;
λ = h/ρ
where ρ is the momentum
So first we will find the momentum, momentum(ρ) = mv
m is the mass and v is the velocity, the mass must be in kilogram
So from the question, mass (m) = 200g converting this to kilogram, mass(m) =200/1000=0.2kg
v =17m/s
We can now substitute our values in ρ = mv and solve for momentum
Momentum(ρ) = mv
=0.2×17
=3.4 kgm/s
ρ = 3.4 kgm/s
We can now proceed to find the deBoglie wavelength
deBoglie wavelength(λ) = h/ρ h is a constant = 6.626×10⁻³⁴ j.s
deBoglie wavelength(λ) = h/ρ
= 6.626×10⁻³⁴/3.4
=1.95 ×10⁻³⁴ m
Therefore the deBoglie wavelength is 1.95 ×10⁻³⁴ m
