Respuesta :
Answer:
t = 108.33 nm
Explanation:
we know that for destructive interference we have following relation
[tex]2t =(m+\frac{1}{2}) \frac{\lambda}{n}[/tex]
for minimum thickness m =0
therefore we have
[tex]t = \frac{lambda}{4n}[/tex]
where [tex]\lambda = 650 nm[/tex]
refrective index n = 1.5
putting all value to get required value of thickness
[tex]t = \frac{650}{4*1.5}[/tex]
t = 108.33 nm
Answer:
108.33 nm
Explanation:
For destructive interference the thickness [tex]2t=(m+\frac{1}{2})\frac{\lambda }{n}[/tex] , for minimum m=0
So [tex]2t=\frac{\lambda }{2n}[/tex]
[tex]t=\frac{\lambda }{4n}[/tex]
Here [tex]\lambda[/tex] is wavelength and n is order of index
So [tex]=\frac{\lambda }{4n}=\frac{650}{4\times 1.5}=108.333nm[/tex]
So the least non zero thickness for destructive interference is 108.33 nm
