Answer:
[tex] 9.40\times 10^{-11} [/tex]
Explanation:
n = order of excited state of the ion = 4
z = atomic number of lithium atom = 3
Radius of ion in nth excited state is given as
[tex]r_{n} = (5.29\times 10^{-11}) \frac{n^{2}}{z^{2}}[/tex]
for n = 4 and z = 3
inserting the values
[tex]r_{4} = (5.29\times 10^{-11}) \frac{4^{2}}{3^{2}}[/tex]
[tex]r_{4} = 9.40\times 10^{-11} [/tex]
