Answer:
a) 30.82 m/s
b) 183.33 Hz
Explanation:
a)
V = speed of the sound = 339 m/s
v = speed of the train = ?
f' = observed frequency by the observer = 220 Hz
f = actual frequency of the observer = 200 Hz
using the equation
[tex]f' = \frac{fV}{V - v}[/tex]
[tex]220 = \frac{(200)(339)}{339 - v}[/tex]
v = 30.82 m/s
b)
V = speed of the sound = 339 m/s
v = speed of the train = 30.82 m/s
f'' = observed frequency by the observer as train moves away = ?
f = actual frequency of the observer = 200 Hz
using the equation
[tex]f'' = \frac{fV}{V + v}[/tex]
[tex]f'' = \frac{(200)(339)}{339 + 30.82}[/tex]
f'' = 183.33 Hz