Answer:
Energy of photon, E = 12.43 eV
Explanation:
It is given that,
Wavelength of UV vacuum, [tex]\lambda=100\ nm=10^{-7}\ m[/tex]
Energy of photon is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
h = Planck's constant
c = speed of light
[tex]E=\dfrac{6.64\times 10^{-34}\times 3\times 10^8}{10^{-7}}[/tex]
[tex]E=1.99\times 10^{-18}\ J[/tex]
or
[tex]E=\dfrac{1.99\times 10^{-18}}{1.6\times 10^{-19}}\ eV[/tex]
E = 12.43 eV
So, the energy of the photon is 12.43 eV. Hence, this is the required solution.
