Respuesta :
Answer:
50.04 m
Explanation:
Weight of car = 1.8 x 10^4 N
u = 0
F = 5 x 10^3 N east
Let d be the displacement in the position of car in 6 s.
Mass of car, m = Weight / g = 1.8 x 10^4 / 10 = 1.8 x 10^3 kg
Force = mass of car x acceleration of car
a = F / m = 5 x 10^3 / ( 1.8 x 10^3) = 2.78 m/s^2
Use third equation of motion
s = u t + 1/2 a t^2
d = 0 + 1/2 x 2.78 x 6 x 6
d = 50.04 m
Answer:
Displacement = 50.04 m
Explanation:
Given,
Weight of car, W = 1.8 × 10⁴ N
Initial Velocity, u = 0
Force, F = 5 × 10³ N (at the East direction)
Time, t = 6s
Let 'd' be the displacement in the position of car in 6 seconds.
Mass of car , m = Weight/Gravity
m = 1.8 × 10⁴ N / 10 m/s²
m = 1.8 × 10³ kg
Now,
Force of car = Mass of car × acceleration of car
So, Acceleration = Force/Mass
Acceleration = 5 × 10³ N/1.8 × 10³ kg
Acceleration = 2.78 m/s²
By using the formula of second equation of motion.
s = ut + 1/2 at²
where, u = 0
So,
s = 1/2 at²
s = 1/2 × 2.78 × 6²
s = 1/2 × 2.78 × 36
s = 50.04 m
Here, s is 'd'. 's' and 'd' both are displacement.
