Answer:
The distance on the screen from the central maxima to the second order bright line is 6.33 mm
Explanation:
It is given that,
Wavelength of lase light, [tex]\lambda=633\ nm=633\times 10^{-9}\ m[/tex]
Separation between slits, d = 0.4 mm = 0.0004 m
Distance between screen and slits, D = 2 m
We need to find the distance on the screen from the central maxima to the 2nd Order bright line. It can be calculated using :
[tex]Y=\dfrac{n\lambda D}{d}[/tex]
n = 2
[tex]Y=\dfrac{2\times 633\times 10^{-9}\times 2}{0.0004}[/tex]
Y = 0.00633 m
or
Y = 6.33 mm
So, the distance on the screen from the central maxima to the second order bright line is 6.33 mm. Hence, this is the required solution.
