Answer:
0.326 m
Explanation:
Given mass = 0.5 kg
spring constant K = 40 N/m
Angle of plane [tex]\Theta =30^{\circ}[/tex]
The initial energy is given by [tex]\frac{Kx^2}{2}[/tex]
And the final energy is given by [tex]mgsin\Theta \times d[/tex]
According to energy conservation
Initial energy = final energy
[tex]\frac{Kx^2}{2}=mgsin\Theta \times d[/tex]
[tex]d=\frac{0.8}{0.5\times 9.81\times sin30}=0.326m[/tex]
