the equation is p1 x v1 divided by T1 = p1 x v2 = T2 but since the pressure is kept constant you do not even need it so the equation would now be v1 divided by t1 = v2 divided by t2
2135 cm3 divided by 127 degrees celcius = x divided by 206
answer: 3460 cm3
Answer:
The volume of the sample if the temperature is increased to 206°C when the pressure is kept constant is 3,463.07 cm³.
Explanation:
Charles's Law consists in the relationship between the volume and temperature of a certain amount of ideal gas, where constant pressure is maintained. The relationship is produced by means of a constant of proportionality. Then, at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.
In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:
[tex]\frac{V}{T}=k[/tex]
It is now possible to assume that you have a certain volume of V1 gas that is at a temperature V1 at the beginning of the experiment. If you vary the volume of gas to a new V2 value, then the temperature will change to T2, and it will be met:
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
In this case:
Then:
[tex]\frac{2135 cm^{3} }{127 C} =\frac{V2}{206 C} \\[/tex]
Solving you get:
[tex]V2=\frac{2135 cm^{3} }{127C} *206 C[/tex]
V2=3,463.07 cm³
The volume of the sample if the temperature is increased to 206°C when the pressure is kept constant is 3,463.07 cm³.
