Answer:
a) v=1.36f
b)m=.36
c) real
d) Inverted
Explanation:
a)
In this question we have given,
object distance from converging lens,u=-3.78f
focal length of converging lens,=f
we have to find location of image,v=?
and magnification,m=?
we know that u, v and f are related by following formula
[tex]\frac{1}{f} =\frac{1}{v}- \frac{1}{u}[/tex].............(1)
put values of f u in equation (1)
we got,
[tex]\frac{1}{f} =\frac{1}{v}- \frac{1}{-3.78f}[/tex]
[tex]\frac{1}{f}-\frac{1}{3.78f} =\frac{1}{v}[/tex]
[tex]\frac{2.78}{3.78f} =\frac{1}{v}[/tex]
or
v=1.36f
b) Magnification, [tex]m=\frac{v}{u} \\m=\frac{1.36f}{3.78f}\\m=.36[/tex]
c)
Here the object is located further away from the lens than the focal point therefore image is real image and inverted.
d) image is inverted
