Answer:
Distance, s = 399.42 m/s
Explanation:
It is given that,
Initial velocity of drag racer, u = 0
Final velocity of drag racer, v = 407 km/hr = 113.056 m/s
Acceleration, [tex]a=16\ m/s^2[/tex]
Third equation of motion is :
[tex]v^2-u^2=2as[/tex]
s is the distance traveled
[tex]s=\dfrac{v^2-u^2}{2a}[/tex]
[tex]s=\dfrac{v^2}{2a}[/tex]
[tex]s=\dfrac{(113.056)^2}{2\times 16}[/tex]
s = 399.42 m/s
So, the distance traveled during this acceleration is 399.42 m/s. Hence, this is the required solution.
