Answer:
Acceleration, [tex]a=11.62\ m/s^2[/tex] (west)
Explanation:
Initial velocity, u = 15 m/s
Final velocity, v = 35 m/s
Displacement, d = 43 m
We need to find the magnitude of acceleration. Here, both initial and final velocities are in same direction i.e. west, so we have to take both velocities positive. It can be calculated using third equation of motion as :
[tex]v^2-u^2=2ad[/tex]
[tex]a=\dfrac{v^2-u^2}{2d}[/tex]
[tex]a=\dfrac{(35\ m/s)^2-(15\ m/s)^2}{2\times 43\ m}[/tex]
[tex]a=11.62\ m/s^2[/tex]
So, the acceleration of the object is [tex]11.62\ m/s^2[/tex] (west) . Hence, this is the required solution.
