What is the highest possible theoretical efficiency of a heat engine operating with a hot reservoir of furnace gases at 727°C when the cooling water available is at 27°C ?

Respuesta :

Answer:

[tex]\eta_{max} = 70%[/tex]

Explanation:

given data:

maximum temperature = 727 degree C =727 +273 = 1000 K

Minimum temperature = 27 degree C = 27 +273 = 300 K

Maximum efficiency is given as [tex]\eta[/tex]

[tex]\eta = \frac{T_{max} - T_{min}}{T_{max}} *100%[/tex]

plugging all value from the above to get maximum efficiency

[tex]\eta = \frac{1000-300}{1000} *100%[/tex]

[tex]\eta_{max} = 70%[/tex]

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