Answer:
It radiates at a rate of [tex]15506.98Wm^{-2}[/tex]
Explanation:
We shall use Stefan–Boltzmann law to calculate radiant emission of energy
According to Stefan–Boltzmann law we have
[tex]P=e\sigma AT^{4}[/tex]
For a perfect black body we have 'e' =1
It is given surface temperature = [tex]450^{o}C=723.15 Kelvins [/tex]
Thus applying values in the above equation we have
energy per unit surface area=
[tex]\frac{P}{A}=e\sigma T^{4}\\\\\therefore \frac{P}{A}=1\times 5.67\times 10^{-8}\times 723.15^{4}\\\\\frac{P}{A}=15506.98Wm^{-2}[/tex]
