Answer:
[tex]A_{\triangle ADC}=6\ un^2 .[/tex]
Step-by-step explanation:
The area of initial triangle and the area of reflected triangle are the same, so
[tex]A_{\triangle ABC}=A_{\triangle ADC}[/tex]
Find the area of triangle ABC using formula
[tex]A_{\triangle}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}[/tex]
In triangle ABC:
- base = AC = 4 units
- height = BE = 3 units
So,
[tex]A_{\triangle ABC}=\dfrac{1}{2}\cdot 4\cdot 3=6\ un^2 .[/tex]
Hence,
[tex]A_{\triangle ADC}=6\ un^2 .[/tex]
