Respuesta :
Answer:
14 seconds
Explanation:
Distance covered by sports car is measured with 21*t where t is time.
Distance covered by police is measured with at^2/2(t-time, a-acceleration) as it doesnt have starting velocity. If the distances are equal(police catches sport car)
then we have 21t=3/2*t^2 Solving this equation we get t=14 & t=0;
excluding the starting point we have 14 seconds
Answer:
t = 14 seconds
Explanation:
As we know that the speed of the car which passes the police car is 21 m/s
so the distance moved by that car in next "t" seconds is given as
[tex]d = v t[/tex]
[tex]d = (21) t[/tex]
now we know that police car starts from rest at constant acceleration a = 3 m/s/s
so the distance moved by that car is given as
[tex]d = v_i t + \frac{1}{2} at^2[/tex]
[tex]d = 0 + \frac{1}{2}3 t^2[/tex]
now if police catch the speeding car after "t" seconds so we have
[tex]21 t = \frac{1}{2}(3) t^2[/tex]
[tex] t = 14 s[/tex]
