Answer:
[tex]\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}[/tex]
Explanation:
The formula for the amount heat q absorbed by a substance is
q = mcΔT
where
m = the mass of the substance
C = the specific heat capacity of the material
ΔT = the temperature change
Data:
q = 2267 J
m = 44.5 g
T₁ = 33.9 °C
T₂ = 288.3 °C
Calculations:
ΔT = (288.3 - 33.9) °C = 254.4 °C
[tex]\begin{array}{rcl}2267 & = & 44.5 \times C \times 254.4\\2267 & = & 11 180C\\C& = & \dfrac{2267}{11180}\\\\& = & \textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}\\\end{array}[/tex]
[tex]\text{The specific heat capacity of the metal is \boxed{\textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}[/tex]
