Answer: Moles of oxygen needed to burn given amount of octane is 16.875 moles.
Explanation:
We are given:
Moles of octane burned = 1.35 mol
For the given chemical reaction:
[tex]2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(g)[/tex]
By Stoichiometry of the reaction:
When 2 moles of octane is burnt, then 25 moles of oxygen are needed
So, when 1.35 moles of octane is burned, then = [tex]\frac{25}{2}\times 1.35=16.875mol[/tex] of oxygen are needed.
Hence, moles of oxygen needed to burn given amount of octane is 16.875 moles.
