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Given: G = 6.67259 × 10−11 N m2 /kg2
A 944 kg meteor comes in from outer space and impacts on the a moon’s surface (this moon is not necessarily the Earth’s moon). The mass of this moon is M = 7 × 1022 kg, and the radius of this moon is R = 1.5 × 106 m. How much work is done by the Moon’s gravitational field? Answer in units of J.

Respuesta :

Answer:

Work done W 2.938*10^9 J

Explanation:

given data:

mass m = 944 Kg

Mass of moon M = 7*10^22 Kg

Radius of the moon R = 1.5*10^6 m

gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2

we know that work done is given as

Work done [tex]W = \frac{GMm}{R}[/tex]

                      [tex]= \frac{6.67*10^{-11}*7*10^{22}*944}{1.5*10^6 m}[/tex]

                      = 2.938*10^9 J

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