19-08-2019
Mathematics

contestada

Product tan1°.tan2°.tan3º......tan89° is:
(a) 1
(0) 0
(b)-1
(d) 90

Please answer in a little bit detail

Respuesta :

19-08-2019

[tex]\sin(x) = \cos(90-x) <=> \frac{sin(x)}{cos(90-x)} = 1\\\prod_{n=1}^{89}\tan(n) = \frac{\sin(1)}{\cos(1)} \cdot \frac{sin(2)}{cos(2)}...\frac{sin(89)}{cos(89)} = 1[/tex]

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