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If the solubility of copper chloride (CuCl2) is 151 g/dm3, how much copper chloride can be dissolved in 7.8 dm3 of water?

Respuesta :

Edufirst

Answer:

  • 1,200 g (rounding to two significant figures).

Explanation:

1) Data:

a) S = 151 g/dm³

b) mass = x

c) V = 7.8 dm³³

2) Formula for solubility, S:

  • S = mass of solute / volume of solvent.

3) Solution:

  • Substitute the data into the formula:

         151 g/ dm³ = x / 7.8 dm³

  • Solve for x:

       x = 151 g/dm³ × 7.8 dm³ = 1,177.8 g.

Round to two significant figures (7.8 dm³ has two sig. fig.): 1,200 g

Answer:

1177.8

Explanation:

answer to educure

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