Answer:
[tex]I(t)=4[1-e^{-2t}][/tex]
Explanation:
For a LR circuit as shown the current at any time t in the circuit is given by
[tex]I(t)=\frac{V}{R}[1-e^{\frac{-Rt}{L}}][/tex]
where
'V' is the voltage
'R' is resistance in the circuit
'L' is the inductance of the circuit
't' is time after circuit is turned on
Applying the given values we get
[tex]I(t)=\frac{32}{8}[1-e^{\frac{-8t}{4}}]\\\\I(t)=4[1-e^{-2t}][/tex]
