What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal to 0.25 and the maximum voltage of the AC source is 8 V?

Respuesta :

Answer:

0.08 w

Explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=[tex]V_r[/tex][tex]I_r[/tex] cosΦ

We have given maximum voltage =8 volt

[tex]V_r[/tex]=[tex]\frac{8}{1.414}[/tex]

power factor =.25

resistance =25Ω

power factor =[tex]\frac{R}{Z}[/tex]

power factor=[tex]\frac{25}{Z}[/tex]

From here Z=100

P=[tex]\frac{8}{1.414}[/tex] ×[tex]\frac{v_r}{Z}[/tex] ×cosΦ

=5.6577×0.05677×0.25

=0.08w

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