Answer:
[tex]M = 8 \times 10^{-4} H[/tex]
Explanation:
As per the condition of mutual inductance of the coil we know that flux linked with coil 2 is proportional to the current in the coil 1
so here we will have
[tex]\phi_2 = M i_1[/tex]
here we know that rate of change in flux is equal to the EMF induced in the coil
so we will have
[tex]\frac{d\phi_2}{dt} = M \frac{di_1}{dt}[/tex]
so we have
[tex]EMF = M \frac{di}{dt}[/tex]
now plug in all values in it
[tex]4 \times 10^{-3} = M (5)[/tex]
[tex]M = 8 \times 10^{-4} H[/tex]
