Answer:
[tex]Q_{L}[/tex]= 41.66 KW
Explanation:
In a refrigerator COP = [tex]\frac{Q_{L} }{W_{In} } =\frac{T_{L} }{T_{H}-T_{L} }[/tex]
where [tex]Q_{L}[/tex]= desired cooling effect
[tex]W_{in}[/tex]= work input= 10 KW
[tex]T_{L}[/tex]= 250 K
[tex]T_{H}[/tex]= 310 K
putting the values
[tex]\frac{Q_{L} }{W_{In} } =\frac{250}{310-250}[/tex]
[tex]Q_{L}[/tex]= 41.66 KW
