Answer:
8377 turns
Explanation:
Given:
Mean radius of toroid = 26 cm
Circular cross-section radius, r = 1.9 cm = 0.019
Length of the wire, l = 1000 m
The number of turns (n) on the coil is given by
[tex]n = \frac{l}{s}[/tex]
where,
l is the length of the wire
s is the circumference of the circular wire
⇒[tex]n = \frac{1000}{2\pi r}[/tex]
or
[tex]n = \frac{1000}{2\pi \times 0.019}[/tex]
or
n = 8376.57 or 8377 turns
hence, the number of turns on the coils is 8377
The number of turns of the coil is determined as 8377 turns.
The number of turns of the superconducting wire is calculated as follows;
n = L/2πr
where;
Substitute the given parameters and solve for the number of turns of the coil,
n = 1000/(2π x 0.019)
n = 8377 turns
Thus, the number of turns of the coil is determined as 8377 turns.
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