Answer: (c.) contrapositive
Explanation:
Statement 1 ⇒ If a <0 and b<0 then, (a[tex]\times[/tex]b)<0
Statement 2 ⇒ If (a[tex]\times[/tex]b)>0, then a >0 and b>0
Lets assume that,
a is not negative be A
b is not negative be B
(a[tex]\times[/tex]b) is not negative be C
then,
Statement 1 ⇒ (¬A ∧ ¬B) ⇒(¬C)
Statement 2 ⇒ C ⇒ (A ∧ B)
Hence, the statement is contrapositive.
