Answer:
- 1
Step-by-step explanation:
Using the rules of exponents
[tex]a^{0}[/tex] = 1
[tex](a^n)^{m}[/tex] = [tex]a^{nm}[/tex]
Given
27[tex]a^{0}[/tex][tex](-\frac{1}{3}) ^{3}[/tex]
Note [tex]a^{0}[/tex] = 1 for any value of a, thus
= 27 × 1 × - [tex]\frac{1}{3^{3} }[/tex]
= 27 × 1 × - [tex]\frac{1}{27}[/tex] ← cancel the 27 on numerator/ denominator
= 1 × - 1
= - 1
