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What are the coordinates of the point on the directed line segment from K (-5,-4) to L (5,1) that portions the segment into ratio of 3 to 2

What are the coordinates of the point on the directed line segment from K 54 to L 51 that portions the segment into ratio of 3 to 2 class=

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Answer:

4) (1,-1)

Step-by-step explanation:

Let the points be

[tex](x_1,y_1) = K(-5,-4)\\(x_2,y_2) = L(5,1)\\[/tex]

The formula for finding the coordinates of point that divides the line in a:b is:

[tex]x = \frac{bx_1+ax_2}{a+b} \\y = \frac{by_1+ay_2}{a+b}[/tex]

Here x and y are the coordinates of the point that will partition the line into given ratios

Our ratio is 3 to 2,

So,

a=3

b=2

Putting the values in the formula

[tex]x = \frac{(2)(-5)+(3)(5)}{3+2}\\x = \frac{-10+15}{5}\\x =\frac{5}{5}\\ x =1\\y = \frac{(2)(-4)+(3)(1)}{3+2}\\y = \frac{-8+3}{5}\\y = \frac{-5}{5}\\ y = -1[/tex]

Hence, the correct answer is:

4) (1,-1) ..

The coordinate of the point on the directed line segment is (1, -1). Then the correct option is D.

What is coordinate geometry?

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of line, etc.

The coordinates of the point on the directed line segment from K (-5,-4) to L (5,1) portions the segment into a ratio of 3: 2.

Let the coordinate of the point be (x,y).

We know that the section formula

[tex]\rm (x,y) = (\dfrac{m_1x_2+m_2x_1}{m_1+m_2} ,\dfrac{m_1y_2+m_2y_1}{m_1+m_2})[/tex]

We have

m₁: m₂ = 3: 2

(x₁, y₁) = (-5, -4)

(x₂, y₂) = (5, 1)

Then we have

[tex]\rm (x, y) = (\dfrac{3*5 + 2*(-5)}{3+2} , \dfrac{3*1 + 2*(-4)}{3+2})\\\\\\(x, y) = (\dfrac{5}{5}, \dfrac{-5}{5})\\\\\\(x, y) = (1,-1)[/tex]

More about the coordinate geometry link is given below.

https://brainly.com/question/1601567

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